Question

solve by substitution 2x-3y+6=0 and 2x+3y-18=0​

Answer 1

Answer:

Step-by-step explanation:

2x - 3y + 6 = 0    ... Eqn ( 1 )

2x + 3y - 18 = 0   ... Eqn ( 2 )

From Eqn ( 1 ) we get,

⇒ 2x = 3y - 6

Substituting this in Eqn ( 2 ) we get,

⇒ 3y - 6 + 3y - 18 = 0

⇒ 6y - 24 = 0

⇒ 6y = 24

⇒ y = 24 / 6 = 4

⇒ 2x = 3y - 6

⇒ 2x = 3 ( 4 ) - 6

⇒ 2x = 12 - 6

⇒ 2x = 6

⇒ x = 6 / 2 = 3

Hence the value of x is 3 and value of y is 4.

Answer 2

Given :

2x - 3y + 6 = 0... Eq (1)

2x + 3y - 18 = 0... Eq (2)

From ( 1 ),

» 2x = 3y - 6

Substituting in Eq(2),

» 3y - 6 + 3y - 18 = 0

» 6y - 24 = 0

» y = 4

Now,

2x = 3y - 6

» 2x = 3 ( 4 ) - 6

» 2x = 12 - 6

» 2x = 6

» x = 3

Final answer :

x = 3 and y = 4