Question

solve by substitution.
43x + 67y = - 24  and  67x + 43y = 24

Answer 1

43x+ 67y = - 24 and  67x + 43y = 24---------(1)
43x+67y=-24 or x=(-24-67y)/43-------(2)
Substituting(2) in(1),we get
67[(-24-67y)/43]+43y=24
=>(-1608-4489y)/43+43y=24
=>-1689-4489y+1849y=24
=>-1689-2640y=24
=>1713=-2640y
=>y=1713/2640--------------(3)
putting this value of (3) in (2) we'll get value of x.

Answer 2

Answer:

(1,-1)

Step-by-step explanation:

Given : $43x+67y= -24$

            $67x+43y =24$

To Find : Solve by substitution

Solution:

$43x+67y= -24$  ---1

$67x+43y =24$   ---2

Substitute the value of x from 1 in 2

$67(\frac{-24-67y}{43})+43y =24$

$\frac{67(-24-67y)+43\times 43y}{43} =24$

$\frac{-1608-4489y+1849y}{43} =24$

$-1608-2640y =1032$

$-2640y =1032+1608$

$-2640y =2640$

$y=-1$

Substitute the value of y in 1 to get value of x.

$43x+67(-1)= -24$

$43x= -24+67$

$43x= 43$

$x=1$

Thus the solution is (1,-1)