Math, asked by sathipandu5555, 17 days ago

Solve by substitution in given equation
3x+7y=32
7x+3y=48

Answers

Answered by vedhavyas85
0

Step-by-step explanation:

3x+7y=32

3x=32-7y

x= 32-7y/3------(1)

7x+3y=48( given)

substitute eqn1 here

7(32-7y/3)+3y= 48

224-49y+9y÷3 =48

224-49y+9y= 144

-40y=-80

y=2

sub y in any eqn

3x+7y =32

3x + 7(2) =32

3x=18

x =6

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