Solve by substitution in given equation
3x+7y=32
7x+3y=48
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Step-by-step explanation:
3x+7y=32
3x=32-7y
x= 32-7y/3------(1)
7x+3y=48( given)
substitute eqn1 here
7(32-7y/3)+3y= 48
224-49y+9y÷3 =48
224-49y+9y= 144
-40y=-80
y=2
sub y in any eqn
3x+7y =32
3x + 7(2) =32
3x=18
x =6
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