Question

Solve by substitution method

Answer 1

Question:

$2x - \frac{3}{y} = 9 \\ 3x + \frac{7}{y} = 2$

& y≠0

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Answer:

$x = > \frac{78}{25} \\ y = > \frac{25}{ - 23}$

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Step-by-step explanation:

$let \frac{1}{y} = a$

So,

$2x - 3a = 9 \: \: \: \: \: ....(1) \\ 3x + 7a = 2 \: \: \: \: \: ....(2) \\ \: \: \: \: from \: eq.(1) \\ x = > \frac{9 + 3a}{2}$

putting value of x in eq.(2)

$3x + 7a = 2 \\ = > 3( \frac{9 + 3a}{2}) + 7a = 2 \\ = > \frac{27 + 9a}{2} + 7a = 2 \\ = > \frac{27 + 9a + 2(7a)}{2} = 2 \\ = > 27 +9a + 14a = 2(2) \\ = > 25a = 4 - 27 \\ = > 25a = - 23 \\ a = > \frac{ - 23}{25}$

putting value of a in eq.(1)

$= > 2x - 3a = 9 \\ = > 2x - 3( \frac{ - 23}{25}) = 9 \\ = > 2x + ( \frac{69}{25}) = 9 \\ = > 50x + 69 = 25(9) \\ = > 50x = 225 - 69 \\ = > 50x = 156 \\ = > x = \frac{156}{50} \\ x = > \frac{78}{25}$

Since,

$= > a = \frac{1}{y} \\ = > \frac{1}{y} = \frac{ - 23}{25} \\ y = > \frac{25}{ - 23}$

Hence, the value of x is 78/25 & y is 25/-23.

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hope it is clear to uh!!

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