solve by substitution method 2 X + 3 Y is equal to 9 3 X + 4 Y is equal to 5
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2x + 3y = 9 ....(1)
3x + 4y = 5 ....(2)
(1) × 3 => 6x + 9y = 27
(2) ×2 => 6x + 8y = 10
by adding both the equations, we get
y = 17
substitute, the value of y in (1)
2x + 3y = 9
2x + 3(17) = 9
2x + 51 = 9
2x = 9-51
2x = -42
x = -21
=> x = -21 and y = 17
#Hassan
3x + 4y = 5 ....(2)
(1) × 3 => 6x + 9y = 27
(2) ×2 => 6x + 8y = 10
by adding both the equations, we get
y = 17
substitute, the value of y in (1)
2x + 3y = 9
2x + 3(17) = 9
2x + 51 = 9
2x = 9-51
2x = -42
x = -21
=> x = -21 and y = 17
#Hassan
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