solve by substitution method 2 x minus 3 Y is equal to 1 upon 3 X + 4 Y is equal to 14
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2x - 3y = 1
3x + 4y = 14
From eq1 find value of X first
2x = 1 + 3y
x = (1+3y) / 2
Now put value of X in eq 2
3((1+3y)/ 2) + 4y = 14
(3+9y) / 2+ 4y = 14
Now take LCM of LHS we get
(3+9y+8y) / 2 = 14
3 + 17y = 14*2
3 + 17y = 28
17y = 28 - 3
y = 25 / 17
Now to find X put value of Y in eq1
2x - 3(25/17) = 1
2x = 1+ 75/17
2x = (17+75)/17
2x*17 = 92
34x = 92
x = 92/34
x = 46 / 17
Hence X = 46/17 and Y = 25/17
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