solve by substitution method
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this is first one okkk
second one is
2x+3y=8. eq1
2x=2+3y
2*(2+3y/2)+3y=8
4+6y+6y=16
4+12y=16
12y=16-4
y=12/12=1
now x=2+12/2
x=4/2=7
third one
0.2x+0.1y=25. eq1
2x-4-1.6=116
2x-5.6=116
2x=116-5.6
x=110.4/2
x=55.2
0.2*55.2+0.1y=25
0.1y=25-11.04
y=13.96
4th answer is
x=3 and y=11/7
5th answer is
x=5/2 and y=3
6th ans is
x=-19 and y=11
second one is
2x+3y=8. eq1
2x=2+3y
2*(2+3y/2)+3y=8
4+6y+6y=16
4+12y=16
12y=16-4
y=12/12=1
now x=2+12/2
x=4/2=7
third one
0.2x+0.1y=25. eq1
2x-4-1.6=116
2x-5.6=116
2x=116-5.6
x=110.4/2
x=55.2
0.2*55.2+0.1y=25
0.1y=25-11.04
y=13.96
4th answer is
x=3 and y=11/7
5th answer is
x=5/2 and y=3
6th ans is
x=-19 and y=11
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SanjanaRaj1:
yes
ure
sure
are vo jo second eq thi n usse mene 1st m rakh dia
pr waha to 2 hai na ki 32
wo 3 mene cut kiya hai
acha sryy
3rd wale m aapne wrong kr diya
kyuki waha -1.6y hoga na y to aapne likha hi nhi
oops sryyy
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