Question

solve by substitution method



√2x+√3y=0
√3x-√8y=0​

Answer 1

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Answer 2

$\huge{ \boxed{ \green{ \sf{Answer:-}}}}$

We have,

√2x + √3y = 0

√3x - √8y = 0

From Equation (1), We deduce:

⇒ √2x = -√3y

⇒ x = -√3y / √2

Plugging in equation (2),

⇒ √3(-√3y/√2) - √8y = 0

⇒ -3y/√2 - 2√2y = 0

Taking y in common,

⇒ y ( -3/√2 - 2√2) = 0

⇒ y = 0

Then,

⇒ x = -√3 × 0 / √2

⇒ x = 0

Hence,

The required value of x and y:

$\huge{ \boxed{ \red{ \sf{0 \:and \: 0}}}}$

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For solving the above, you can also try using the other ways of solving like:

• Graphical method
• Elimination method
• Cross multiplication method.