solve by substitution method. 2x+3y=10 and y=5 -3/2x
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Answer:x=2
y=2
Step-by-step explanation:
2x+3y=10 ______eq1
y=5-3/2x
3/2x+y=5
3x+2y=10_______eq2
multiply eq1 by 3 and eq2 by 2
6x+9y=30________eq3
6x+4y=20______________eq4
eq3-eq4
6x+9y-6x-4y=30-20
5y=10
y=2
putting y=2
2x+3×2=10
2x=10-6
2x=4
x=2
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