Math, asked by jindori, 1 month ago

solve by substitution method
2x + 3y = 4, 3x - y = -5​

Answers

Answered by IamIronMan0
5

Answer:

 \huge \pink{x =  - 1 \: and \: y = 2}

Step-by-step explanation:

By second equation

3x - y =  - 5 \\ y = 3x + 5

Substitute value of y in first equation

2x + 3y  = 4 \\  \\  \implies2x + 3(3x + 5) = 4 \\  \\  \implies2x + 9x + 15 = 4 \\  \\  \implies11x = 4 - 15 =  - 11 \\  \\ \implies x =  \frac{ - 11}{11}  =  - 1

And

y = 3x + 5 = 3( - 1) + 5  \\  \implies \: y = 5 - 3 = 2

Answered by kamalkpoddar
2

Answer:

x = -1

y = 2

Step-by-step explanation:

The second equation says,

3x - y = -5

or, y = 3x + 5

Let's substitute the value of y we got from the second equation, in the first equation.

2x + 3y = 4

or, 2x + 3(3x + 5) = 4 [substituting value of y = 3x + 5]

or, 2x + 9x + 15 = 4

or, 11x = -11

or, x = -1

Now let's find the value of y.

3x - y = -5

or, -3 - y = -5 [substituting value of x= -1]

or, y = -3 + 5

or, y = 2

Therefore x= -1 and y= 2.

Now just for verification, why did I choose the second equation to get the value of y and not the first? Because it was simpler to solve the value of y in that equation and substitute it, compared to the other equation. It all depends on the more convenient method.

Also, if you want, you can find the value of x and substitute it as well. The answer will be same.

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