Question

Solve by substitution method
2x-8y=10
3x+8y=15
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Answer 1

Step-by-step explanation:

Solve equation [2] for the variable x

Solve equation [2] for the variable x

Solve equation [2] for the variable x [2] 2x = 8y + 10

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1]

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y [1] 20y = 0

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y [1] 20y = 0 [1] y = 0

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y [1] 20y = 0 [1] y = 0 // By now we know this much :

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y [1] 20y = 0 [1] y = 0 // By now we know this much : x = 4y+5

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y [1] 20y = 0 [1] y = 0 // By now we know this much : x = 4y+5 y = 0

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y [1] 20y = 0 [1] y = 0 // By now we know this much : x = 4y+5 y = 0// Use the y value to solve for x

Solve equation [2] for the variable x [2] 2x = 8y + 10 [2] x = 4y + 5// Plug this in for variable x in equation [1] [1] 3•(4y+5) + 8y = 15 [1] 20y = 0// Solve equation [1] for the variable y [1] 20y = 0 [1] y = 0 // By now we know this much : x = 4y+5 y = 0// Use the y value to solve for x x = 4(-0/2202888)+5 = 5

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Answer 2

ANSWER:

Given:

• 2x - 8y = 10
• 3x + 8y = 15

To Find:

• Value of x and y

Solution:

We are given that,

⇒ 2x - 8y = 10

Transposing 8y to RHS,

⇒ 2x = 10 + 8y

Transposing 2 to RHS,

⇒ x = (10 + 8y)/2

On simplifying,

⇒ x = 5 + 4y ------(1)

We are also given,

⇒ 3x + 8y = 15 -----(2)

Substituting value of x from (1) in (2),

⇒ 3(5 + 4y) + 8y = 15

⇒ 15 + 7y + 8y = 15

Transposing 15 to RHS,

⇒ 15y = 15 - 15

⇒ 15y = 0

So,

⇒ y = 0

Substituing value of y in (1),

⇒ x = 5 + 4y

⇒ x = 5 + 4(0)

⇒ x = 5

Hence, value of x and y is 5 and 0 respectively.