Solve By Substitution method 2x+y=35 and 3x+4y=65
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subtract 2x to both sides in the first equation to get y by itself y=35-2x
substitute the modified equation for y in the second equation 3x+4(35-2x)=65
distribute 3x+140-8x=65
combine like terms -5x+140=65
subtract 140 -5x=-75
divide by -5 x=15
plug in x into one of the formulas and solve
2(15)+y=35
30+y=35
y=5, x=15
substitute the modified equation for y in the second equation 3x+4(35-2x)=65
distribute 3x+140-8x=65
combine like terms -5x+140=65
subtract 140 -5x=-75
divide by -5 x=15
plug in x into one of the formulas and solve
2(15)+y=35
30+y=35
y=5, x=15
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