solve by substitution method 2x-y=4; x+y=2
Answers
Answered by
4
2x-y=4
2x-4=y
y=2x-4
Substituting the value if y in equation 2, we get
x+y=2
x+2x-4=2
3x-4=2
3x=6
x=2
Substituing x in equation 2,we get
2+y=2
y=0
Therefore, x =2 and y = 0
2x-4=y
y=2x-4
Substituting the value if y in equation 2, we get
x+y=2
x+2x-4=2
3x-4=2
3x=6
x=2
Substituing x in equation 2,we get
2+y=2
y=0
Therefore, x =2 and y = 0
Answered by
2
substitute x in x+y= 2
which is x=y-2
then put it in 2x-y=4
like this
2(y-2)-2=4
hence the value of y comes to be as
6
then put this value of y in one of the equation
like this
x+6=2
then x value comes to be -4
which is x=y-2
then put it in 2x-y=4
like this
2(y-2)-2=4
hence the value of y comes to be as
6
then put this value of y in one of the equation
like this
x+6=2
then x value comes to be -4
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