Solve by substitution method: 3x − 2y = 1 and 3x + 4y = 7
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Answer:
3x-2y=1
3x= 1+2y
Therefore, x= (1+2y)/3
Substitute x in 2nd equation,
3x+4y=7
3(1+2y/3)+4y=7
3+6y+12y=21
18y=18
Therefore, y=1
Substituting value of y in x=(1+2y)/3
x= (1+2x1)/3= 3/3=1
Therefore, x= 1 and y=1
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