Solve by substitution method. 3x+2y=3. 3y-2x=2
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Given:
3x + 2y = 3 , 3y - 2x = 2
To find:
Solve by substitution method
Solution:
From given, we have,
3x + 2y = 3 ...... (1)
3y - 2x = 2 ...... (2)
consider equation (1)
3x = 3 - 2y
x = 1 - 2/3 y ...... (3)
substitute this value of x in the equation (2)
so, we get,
3y - 2 (1 - 2/3y) = 2
3y - 2 + 4/3y = 2
13/3y = 2 + 2
13/3y = 4
y = 12/13
substitute the value of y in the equation (3)
x = 1 - 2/3 (12/13)
x = 5/13
Therefore, the values of x and y are 5/13 and 12/13
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