Question

solve by substitution method. 3x-4y=16 , 2x-3y=10​

Answer 1

Answer:

3x-4y=16

3x=16+4y

x= 16+4y/3

2x-3y =10

Put the value of x

2 (16+4y)/3 -3y =10

32+ 8y -3y/3=10

32+8y -9y/3 =10

32y -y =30

y= 32-30

y= 2

Step-by-step explanation:

Answer 2

Answer:

3x-4y=16 is first equation.

2x-3y=10 is second equation.

substitute equation second for first

3x-4y-(2x-3y) =16-10

3x-4y-2x-3y =6

x-7y=6 is equation third

x=6+7y is equation fourth

putting the value of x in equation third

6+7y-7y=6

y=1

putting the value of y in equation fourth

x=6+7*1

x=13.