Solve, by Substitution method 3x-y=3 and 9x-2y=9
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Step-by-step explanation:
3x-y=3 ---------------------(1)
9x-2y=9 -------------------(2)
from eqn.(1), we get,
x= 3+y/3 -------------------(3)
substitute eqn.(3) in (2)
9(3+y/3)-2y=9
3(3+y)-2y=9
9+3y-2y=9
9+y=9
y=9-9
y=0
substitute the value of y in eqn.(3)3
x= 3+(0)/3
x= 3/3
x= 1
HENCE THE VALUE OF x is 1 and y is 0
Answered by
2
hell ooooo
it took some time......
3x-y=3 ---------------------(1)
9x-2y=9 -------------------(2)
from (1), we get,
x= 3+y/3 -------------------(3)
substitute eqn.(3) in (2)
9(3+y/3)-2y=9
3(3+y)-2y=9
9+3y-2y=9
9+y=9
y=9-9
y=0
substitute the value of y in eqn.(3)3
x= 3+(0)/3
x= 3/3
x= 1
HENCE THE VALUE OF x is 1 and y is0
elemination method :
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