Solve by substitution method 7x+3y=27;2x+5y=16
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(7x+3y=27)×2
(2x+5y=16)×7
=14x+35y=112
=14x+6y=54
=29y=58
y=58/29=2
y=2
7x+3(2)=27
=7x=27-6
=7x=21
x=21/7=3
=x=3
so this is ur answer
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