Solve by substitution method: 8x-5y+40=0 ; 7x - 2y=0
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8
x = (40+5y)/8
put in eq 2
7×(40+5y)/8 -2y=0
280 + 35y - 16y=0
280 + 19y =0
y= -280/19 put it in eq u will get value of x
put in eq 2
7×(40+5y)/8 -2y=0
280 + 35y - 16y=0
280 + 19y =0
y= -280/19 put it in eq u will get value of x
Answered by
5
this is the value of y
put it in the first equation then you will get the value of x
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