Question

Solve by substitution method 8y -3x+7=0 2x-y+4=0​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

x=−3 and y=−2

Step-by-step explanation:

Let's solve your system by substitution.

8y−3x+7=0;2x−y+4=0

Rewrite equations:

2x−y+4=0;−3x+8y+7=0

Step: Solve2x−y+4=0for y:

2x−y+4=0

2x−y+4+−2x=0+−2x(Add -2x to both sides)

−y+4=−2x

−y+4+−4=−2x+−4(Add -4 to both sides)

−y=−2x−4

-y/-1=-2x-4/-1

(Divide both sides by -1)

y=2x+4

Step: Substitute2x+4foryin−3x+8y+7=0:

−3x+8y+7=0

−3x+8(2x+4)+7=0

13x+39=0(Simplify both sides of the equation)

13x+39+−39=0+−39(Add -39 to both sides)

13x=−39

13x/13=-39/13

(Divide both sides by 13)

x=−3

Step: Substitute−3forxiny=2x+4:

y=2x+4

y=(2)(−3)+4

y=−2(Simplify both sides of the equation)

x=−3 and y=−2