Question

Solve by substitution method, given pair of linear equations

5(y+1)-4(x+3)=29 and 7(y-3)+2(x-6)=25​

Answer 1

Step-by-step explanation:

i) x+y=5 ...(i)

2x−3y=4 ...(ii) (elimination method)

Multiply eqn (i) by 2

2x+2y=10

2x−3y=4

−+−

____________

5y=6

⇒y=

5

6

Substitute y=

5

6

in eqn (i)

x+y=5

x+

5

6

=5

⇒x=

5

5×5

−

5

6

=

5

19

Substitution method

x+y=5 ....(i)

2x−3y=4 ....(ii)

y=5−x ...(iii)

Putting eqn. (3) in (2)

2x−3(5−x)=4

2x−15+3x=4

x=

5

19

y=

5

5×5

−

5

19

y=

5

6

(ii)

Elimination method

3x+4y=10 ...(i)

2x−2y=2 ...(ii)

Answer 2

Answer:

mark as BRAINLIEST

ty

keep smiling