Question

Solve by substitution method(linear equation in two variables ) 2x+3y=0 & 3x+4y=5

Answer 1

Answer:

x=15 and y =-10

Step-by-step explanation:

Given: 2x+3y=0

           3x+4y=5

Using substitution method,

2x+3y=0 ------- 1

3x+4y=5 ------- 2

Substitute the value of x from 1 in 2,

$3(\frac{-3y}{2})+4y=5$

$\frac{-9y}{2} + 4y= 5$

$-9y+8y=10$

$y=-10$

Substitute the value of y in 1,

2x+3(-10)=0

2x=30=0

2x=30

x=30/2

x=15

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Answer 2

Answer: By substitution method

x = 15 and y = -10

Step-by-step explanation:

2x + 3y = 0 ---------Equation (1)

3x + 4y = 5 ---------- Equation (2)

Solving equation (1)

2x = 0-3y

You can either use x to put value or y, i have used x to put value in other equation. However you can use any of them

x =$\frac{-3y}{2}$

Put x = -3y/2 in equation (2)

3x + 4y = 5

$3*\frac{-3y}{2} + 4y = 5\\\\\frac{-9y}{2} +4y = 5$

$\frac{-9y+8y}{2} = 5\\\\\frac{-y}{2} = 5\\y = -10$

Now put the value of y = -10 in any of the equation to get value of x

Putting y = -10 in equation (1)

2x + 3y = 0

2x + 3(-10) = 0

2x -30 = 0

2x = 30

x =15