Question

Solve by substitution method: s-t=3
S/3+ t/2=6

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore s=9:}}$

${\bold{\therefore t=6:}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies s - t = 3 \\ \\ \implies \frac{s}{3} + \frac{t}{2} = 6 \\ \\ \underline \bold{To \: Find: } \\ \implies s = ? \\ \\ \implies t = ?$

• According to given question :

$\bold{By \: substitution \: method : } \\ \implies s - t = 3 \\ \\ \implies s = 3 + t - - - - - (1) \\ \\ \bold{Putting \: value \:of \: s \: in \: second \: equation : } \\ \implies \frac{s}{3} + \frac{t}{2} = 6 \\ \\ \implies \frac{3+ t}{3} + \frac{t}{2} = 6 \\ \\ \implies \frac{6 + 2t + 3t}{6} =6 \\ \\ \implies6 + 5t = 36 \\ \\ \implies 5t = 36 - 6 \\ \\ {\implies t = \frac{30}{5} } \\ \\ \bold{\implies t = 6} \\ \\ \bold{Putting \: value \: of \: t \: in \: (1)} \\ \implies s = 3 + t \\ \\ \implies s = 3 + 6 \\ \\ \bold{\implies s = 9}$

Answer 2

$\huge\boxed{Answer:}$

S = ( 9 )

Given that :-

• s - t = ( 3 )

• s/3 + t/2 = ( 6 )

To find :-

• Value of ( S )

• Value of ( T )

$\huge\mathfrak{Solution:}$

By substitution method :-

s-t =3 -----(1)

s/3 + t/2 = 6 ----(2)

Therefore the first equation is easy, so we convert it into this form:-

s-t = 3

s = 3 +t -----(3)

Now substituting equation (3) in (2)

3+t /3 + t/2 =6

Now we take the LCM of their denominators..except for the RHS..

2×{3+t/3} + 3×{t/2} = 6

6+2t+3t the whole divided by 6 = 6

6+2t+3t = 6×6

2t+3t = 36

5t = 36-6=30

t = 30/5

t =6 -----(4)

Now substitute (4) in (3)

s = 3+6

$\huge\boxed{s = 9}$