solve by substitution method s-t=3, s/3+t/2=6
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s=t+3-----(1)
s/3+t/2=6---(2)
putting value of 1 in 2
t+3/3+t/2=6
2t+6/6+3t/6=6
2t+6+3t=36
5t=30
t=6
putting value of t in 1
s=6+3
s=9
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