Math, asked by motufe4, 14 days ago

Solve by substitution method x-y+1=0 and 3x+2y-12=0​

Answers

Answered by dsk75
2

Answer:

x = 2; y = 3

Step-by-step explanation:

x - y + 1 = 0 ⇒ y = x+1

3x+2y-12 = 0

⇒ 3x + 2(x+1) - 12 = 0

⇒ 3x + 2x +2 - 12 = 0

⇒ 5x = 10

⇒x = 2

y = x+1

⇒ y = 2+1

⇒ y = 3

Answered by sg693363
1

Answer:

x = 2

y = 3

Step-by-step explanation:

Using Substitution method,

x - y + 1 = 0

x = y - 1 ------ (i)

3x + 2y - 12 = 0 ----- (ii)

3(y - 1) + 2y - 12 = 0

3y - 3+ 2y - 12 = 0

5y - 15 = 0

5y = 15

y=\frac{15}{5}

y = 3

x = y - 1

x = 3 - 1

x = 2

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