solve by taking simultaneous equations
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Adding both equations we get:
2a (x+y) = 2 (a^2 + b^2)
a (x+y) = a^2 + b^2 >>>> 1
(x+y) = (a^2 + b^2)/a
Subtacting equation 2 from 1 we get:
2b (x-y) = -2ab
x-y = -a >>>>>>> 2
Adding equation 1 and 2...
2x = b^2/a
x = b^2/2a
Putting value of x in equation 2...
y = b^2/2a + a
y = (2a^2 + b^2)/2a
This is your answer friend....
2a (x+y) = 2 (a^2 + b^2)
a (x+y) = a^2 + b^2 >>>> 1
(x+y) = (a^2 + b^2)/a
Subtacting equation 2 from 1 we get:
2b (x-y) = -2ab
x-y = -a >>>>>>> 2
Adding equation 1 and 2...
2x = b^2/a
x = b^2/2a
Putting value of x in equation 2...
y = b^2/2a + a
y = (2a^2 + b^2)/2a
This is your answer friend....
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