Question

Solve by the attachment​

Answer 1

Focal length (f ) = -15 cm

Distance of image (v) = -10 cm

$\frac{1}{v} -\frac{1}{u} =\frac{1}{f}$

1/u = -(1/10) – (1/- 15)

1/u =1/15 – 1/10

1/u = -0.033

u = -30 cm

so the object is placed 30 cm away from the concave lens.

Ray diagram

Hope this helps u

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