Question

solve by the elimination method 2 x−y=3;3 x+ y=7​

Answer 1

Given equations are

2x+y=7 ....(1)

and 2x−3y=3 ....(2)

Multiply equation (1) by 3,

6x+3y=21 ....(3)

Add equations (2) and (3) to eliminate y, we get

8x=24

⇒x=3

Substitute this value of x in equation (1),

2(3)+y=7

⇒6+y=7

⇒y=1

Therefore, solution is x=3,y=1.