solve by the elimination method 2 x−y=3;3 x+ y=7
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Given equations are
2x+y=7 ....(1)
and 2x−3y=3 ....(2)
Multiply equation (1) by 3,
6x+3y=21 ....(3)
Add equations (2) and (3) to eliminate y, we get
8x=24
⇒x=3
Substitute this value of x in equation (1),
2(3)+y=7
⇒6+y=7
⇒y=1
Therefore, solution is x=3,y=1.
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