Question

solve by the method of (a) elimination and (b) substitution
5m+6n=13
2m-5n=16​

Answer 1

Answer:

Step-by-step explanation:

Let 4m+3n=18 --- (1)

and 3m−2n=5 --- (2)

Multiplying the first equation by 2 , we get 8m+6n=36 -- (3)

Multiplying the second equation by 3 , we get 9m−6n=15 -- (4)

Adding equations 3, and 4 , we get

17m=51

=>m=3

Now, putting m=3 in equation 1 we get, 12+3n=18

=>3n=6

=>n=2

Answer 2

Step-by-step explanation:

in eq.1 n = 13-5m/6

in eq.2 we will substitute the above value = 2m-5(13-5m/6)=16

= 2m-65+25m/6=16

= 22m-390+25m/6=16

= 47m-390 = 96

= m = 390+96/47

m=10