Question

Solve by the method of cross multiplication the pair of equation, 2x+3y+8=0,4x+5y+14=0​

Answer 1

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8x +5y =9

Subtract 8x both sides we get

5y = 9 – 8x

Divide by 5

Y = (9 – 8 x)/5 …(3)

Plug this value of y in equation second we get

3x +2y =4

3x + 2(9 – 8 x)/5) = 4

Multiply by 5 we get

15 x + 18 - 16 x = 20

-x = 2

X = - 2

Plug this value back in equation (3) we get

Y = (9- 8(-2))/5

Y = 25/5

Y = 5

Answer is x = -2 and y = 5

Cross multiplication method

8x +5y =9 …(1)

Subtract 9 both side we get

8x +5y – 9 = 0

3x +2y =4 …(2)

Subtract 4 both side we get

3x + 2y – 4 = 0

Compare with

we get

a1 = 8 , b1 = 5 , and c1 = -9

a2 = 3 , b2 = 2 and c2 = -4

Use the formula of cross multiplication

We get

x = -2 and y = 5

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Answer 2

Answer:

Solution.,

2x+3y=8

x=8-3y/2......(1)...

4x+5y+14=0

x=-14-5y/4........(2).....

From EQN....1 ...AND ....2...,WE GOT,

8-3y/2=-14-5y/4

8-3y=-14-5y/2

16-6y=-14-5y

-6y+5y=-14-16

-y=-30

y=30

Substitute the value of y in EQN..1...

x=8-3y/2

x=8-3×30/2

x=8-90/2

x=4-45

x=-41

{ x = -41 AND y = 30 }. Answer.........

IT WILL HELP YOU A LOT !