Question

solve by the method of substitution √2x+√3y =2 , 2√2x + y =4​

Answer 1

Answer:

√2x+√3y,=2

√x=2-√3y

2√2x +y=4

2√2(2-√3y)+y=4

4√2-2√6y +y=4

-√6y=4-4√2

√6y=-√2

√3y=1

y=1/√3

now,

√2x+√3y=2

√2x+√3*1/√3=2

√2x=1

x=1/√2

x=1/√2. and y=1/√3