Math, asked by neetarughani1981, 10 months ago

Solve by the method of substitution : 4/X + 9/y = 1/2 and 12/ x + 12/ y = 1 : x.y not= 0​

Answers

Answered by riteshkumar90359
7

Answer:

x=20 and y =30

Step-by-step explanation:

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Answered by tripathi64
0

Answer:

The values of x and y in the given equation by substitution method is x=20 and y=30 for  x\neq 0 and y\neq 0

Step-by-step explanation:

Given equations are \frac{4}{x}+\frac{9}{y}=\frac{1}{2}\hfill (1)

and \frac{12}{x}+\frac{12}{y}=1\hfill (2)  for x\neq 0 and y\neq 0

Now solving the given equations by substitution method :

Let a=\frac{1}{x} and b=\frac{1}{y} for x\neq 0 and y\neq 0

Equation (1) implies 4a+9b=\frac{1}{2}\hfill (3)

Equation (2) implies 12a+12b=1\hfill (4)

From equation (3) 4a+9b=\frac{1}{2}

4a=\frac{1}{2}-9b

a=\frac{\frac{1}{2}-9b}{4}

a=\frac{1}{8}-\frac{9b}{4}

  • Now substitute the value of "a" in equation (4)

12(\frac{1}{8}-\frac{9b}{4})+12b=1

\frac{12}{8}-\frac{108b}{4}+12b=1

\frac{3}{2}-27b+12b=1

-15b=1-\frac{3}{2}

-15b=\frac{2-3}{2}

-15b=-\frac{1}{2}

b=\frac{1}{2\times 15}

b=\frac{1}{30}

Since b=\frac{1}{y}  for  y\neq 0

b=\frac{1}{30}=\frac{1}{y} for  y\neq 0

Therefore y=30

  • Substitute the value of b in equation a=\frac{1}{8}-\frac{9b}{4} we get

a=\frac{1}{8}-\frac{9(\frac{1}{30})}{4}

=\frac{1}{8}-\frac{\frac{9}{30}}{4}

=\frac{1}{8}-\frac{9}{120}

=\frac{1}{8}-\frac{3}{40}

=\frac{5-3}{40}

=\frac{2}{40}

a=\frac{1}{20}

Since a=\frac{1}{x} for x\neq 0

a=\frac{1}{20}=\frac{1}{x} for x\neq 0

Therefore x=20

Therefore x=20 and y=30

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