Solve by the method of substitution
i) x - 1/3y = 6 and 2x + 3y = 23
Answers
Answered by
0
Given: 2x+3y=13 ------(1)
4x+5y=23 ------(2)
From equation (1),
2x+3y=13
y=313−2x
Substitute the value of y in equation (2):
4x+5y=23
4x+5(313−2x)=23
12x+65−10x=69
2x=69−65
2x=4
x=2
Then substitute the value of x in equation (1):
2(2)+3y=13
4+3y=13
3y=13−4
3y=9
y=3
Therefore solution is x=2 ans
Answered by
0
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