Solve by the substitution method :3x-(y+7)/(11 )+2 =10 and 3x+3y =65
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Answer:
3x - y + 711 + 2 = 10 ---------------- ( 1 )
And
3x + 3y = 65 ----------------- ( 2 )
First we simplify equation 1 , As :
By taking L.C.M. , we get
⇒33x - 11y + 7 + 22 = 110
⇒33x - 11y = 81 ------- ( 3 )
From equation 2 , we get
⇒ y = 653 - x ( Substitute that value of y in equation 3 and get
⇒33x - 11 ( 653 - x ) = 81
⇒33x - 7153 + 11x = 81
⇒44x = 81 + 7153
⇒44x = 9583
⇒x = 958132
x = 7.25 Now We , substitute that value of x in equation 2 and get
⇒3 ( 7.25 ) + 3y = 65
⇒3y = 65 - 21.75
⇒3y = 43.25
⇒y = 14.416
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