Question

solve by trail and error 5y=20​

Answer 1

Step-by-step explanation:

5y=20

Let's take y as 2

5×2=10

Not 2

Let's take y as 3

5×3=15

Not 3

Let's take y as 4

5×4=20

Therefore,'y' is 4(by trail and error method)

Answer 2

IN trail and error method we give a random value to the variable and check if that is correct. But mostly it isn't advisable to use this method for algebra. But as a new learner we can use it for only a few questions. So here-

- Let's try giving 'y' the value of 2

• 5 × 2 = 10

∴ Here we know 2 isn't the value of y.

- Let's try giving 'y' the value of 3

• 5 × 3 = 15

∴ Here we know 3 isn't the value of y.

- Let's try giving 'y' the value of 4

• 5 × 4 = 20

∴ We can conclude that y is equal to 4.

Hope this helps you. Pls mark as brainliest answer.