Question

Solve by trial and error method: 2z+1=7.​

Answer 1

Answer:

Z = 3

Step-by-step explanation:

2z + 1 = 7

2z = 7 - 1

2z = 6

z = 6/2

z = 3

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Answer 2

Answer:

z = 3 is always a solution.

Step-by-step explanation:

$put \: z = 1 \\ \\ 2 + 1 = 7 \: \: not \: true \\ \\ put \: z = 2 \\ \\ 4 + 1 = 7 \: \: \: \: \: \: not \: true \\ \\ put \: z = 3 \: \: \: \: \: \: \: \: \: \: 6 + 1 = 7 \: \: always \: true \\ \\ \: \\ \\ therefore \: \: z = \: is \: a \: solution \: b y \: \: trial \: and \: error.$