Question

solve by trigonometry​

Answer 1

Answer:

(i) right angled

(ii) ∠MNO = 90°

(iii) ∠NMO = 45°

I hope θ will be ∠MON . So,

(iv) sinθ = sin45° = 1/√2.

(v) cosθ = cos45° = 1/√2.

(vi) 1 = (MN/MO)² + (NO/MO)².

(vii) 1 = sin²θ + cos²θ