Question

solve by using cross multiplication method 5/x-1 + 1/y-2 =2 6/x-1 - 3/y -2 =1​

Answer 1

Answer:

x = 4 and y = 5

Step-by-step explanation:

given,

$\frac{5}{x-1} + \frac{1}{y-2} = 2\\ \frac{6}{x-1} + \frac{3}{y-2}  = 1$

let take,

$\frac{1}{x-1} = p\\\\\frac{1}{y-2} =q$

now given equation will be,

5p + q = 2   ..................(1)

6p - 3q = 1  ...................(2)

multiply eqn(1) by 3     and add eqn (2) from that new equation

15p + 3q = 6

6p - 3q  = 1

--------------------

21 p +  0 = 7

--------------------

p = $\frac{1}{3}$

Apply this in any one equation will get,

q = $\frac{1}{3}$

now,

we know,    $\frac{1}{x-1} = p\\\\\frac{1}{y-2} =q$

from that,

x= 4 and y=5

Answer 2

you Have to convert them into fractions and assume as any variable.