Question

solve by using elimination method

Answer 1

here's your answer
if its wrong please tell me

Answer 2

x-5 = y + 3

x-y = 3+5= 8

(x - y = 8) - eqn 1

2(x - y = 8)

2 y + x= 3

x+2 y = 3 - eqn 2

add eqn 2 and eqn 1

x + 2 y =3

2 x - 2 y = 16

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3 x = 19

x = $\frac{19}{3}$

substitute x=$\frac{19}{3}$ in eqn 2

x + 2 y = 3

$\frac{19}{3}$ + 2 y = 3

2 y = 3 -$\frac{19}{3}$

2 y = $\frac{9 - 19}{3} = \frac{-10}{3}$

y = $\frac{-10}{3×2 }$

y = $\frac{-5}{3}$