Question

solve by using formula 4xsquare=4x—1
$4x {}^{2} = 4x - 1$
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Answer 1

Answer:

4x² = 4x - 1

∴4x² - 4x + 1 = 0

∴ (2x)² - 2.(2x).(1) + 1 = 0

∴ (2x + 1)² = 0

∴ (2x + 1) = 0

∴ 2x = -1

∴ x = -1/2

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Answer 2

Given Quadratic equation → 4x² - 4x + 1 = 0

All Quadratic equations can be expressed in the general form ax² + bx + c.

Here

• a = 4
• b = -4
• c = 1

Solve by using Quadratic formula

$\bf{x = \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }$

$\implies \sf{x = \dfrac{ - ( - 4) \pm \sqrt{( - 4)^{2} - 4(4)(1)} }{2(4)} }$

$\implies \sf{x = \dfrac{4 \pm \sqrt{16 - 16} }{8} }$

$\implies \sf{x = \dfrac{4 \pm \sqrt{0} }{8} }$

Since the discriminant of this equation is 0, equation will have real and equal roots.

∴ x = 1/2

KNOW MORE:

There are 3 methods of factorising any Equation. Any method can be followed.

1. Splitting the middle term
2. Applying Quadratic formula
3. Completing the square method