Question

Solve By using formula methos
$6 \sqrt{3x {}^{2} } + 7x - \sqrt{3}$
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Answer 1

Answer:

Step-by-step explanation:

Given that,

Let p ( x ) = 6√3x² + 7x - √3 = 0

Comparing p ( x ) with ax² + bx + c = 0,

We have a = 6√3 , b = 7 and c = - √3

∴ x = - b ± √ b² - 4ac /2a

= - 7 ± √ ( 7 )² - 4 ( 6√3 ) ( - √3 ) / 2 ( 6√3 )

= - 7 ± √ 49 + 72 / 12√3

= - 7 ± √ 121 / 12√3

= - 7 ± 11 / 12√3

= ( - 7 - 11 / 12√3 ) or ( - 7 + 11 / 12√3 )

= ( - 18 / 12√3 ) or ( 4 / 12√3 )

= ( - 3 / 2√3 ) or ( 1 / 3√3 )

= ( - 3√3 / 2 ) or ( √3 / 3 ) is the answer. (∵ Rationalising the denominator )