Solve by using formula:- x = -b ± √b²-4ac/ 2a y^2-6y+2=0
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Answer:
For the nature of the roots we have to find the discriminant of the given equation
D = b²-4ac
= 48-48
D = 0
thus the roots are real and equal
it is the perfect square of √3x - 2
so (√3x-2)²=0
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No solution when D = b2 − 4ac < 0 : a2 + 64 > 0 for all real numbers a. So for every real a the equation has a solution. 11 (4). { x + 3y = 5. 2x + y ...
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