Math, asked by tannuanjesh, 4 months ago

solve by using identities (x+10) (x+5) , (2p+5) (2p+1)​

Answers

Answered by zeesoftzs
1

Step-by-step explanation:

(x +a )(x + b) =  {x}^{2}  + ( a+ b)x + ab \\ (x + 10)(x + 5) =  {x}^{2}  + (10 + 5)x + 5 \times 10 \\  =  {x}^{2}  + 15x + 50 \\ (2p + 5)(2p  + 1) = ( {2p)}^{2}  + (5 + 1)(2p) + 5 \times 1 \\  = 4 {p}^{2}  + 12p + 5

Answered by harmeetsingh33
0

x2 common (10) (5) , 2p2 common (5) (1)

2x =50 , 4p2= (5)

x=2÷50,p2=4÷5

0.04,0.8

Similar questions