solve by using laws 2^-3*(-7)^-3
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Answer:
Step-by-step explanation:
2⁻³ × (-7)⁻³
LAWS OF EXPONENT
- aᵐ × aⁿ = aᵐ ⁺ ⁿ
- aᵐ ÷ aⁿ = aᵐ ⁻ ⁿ
- a⁻ᵐ = 1/aᵐ
- a⁻¹ = 1/a
- (ab)ᵐ = aᵐ × bᵐ
- (a/b)ᵐ = aᵐ / bᵐ
- a⁰ = 1
Thanks !
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