Math, asked by jkkavinkumar09, 4 hours ago

solve by using laws 2^-3*(-7)^-3​

Answers

Answered by dipikachoudhury266
2

Step-by-step explanation:

Hope you find it helpful

Attachments:
Answered by Anonymous
4

Answer:

 \dfrac{ - 1}{2744}

Step-by-step explanation:

2⁻³ × (-7)⁻³

 =    \bigg(\dfrac{1}{2}  \bigg)^{3}  \times \bigg(\dfrac{1}{ - 7}  \bigg)^{3}

 =  \bigg( \dfrac{1}{2}  \times  \dfrac{1}{ - 7}   \bigg) ^{3}

 = \bigg(\dfrac{1}{ - 14}  \bigg)^{3}

 =  \dfrac{ - 1}{2744}

 \\

LAWS OF EXPONENT

  1. aᵐ × aⁿ = aᵐ ⁺ ⁿ
  2. aᵐ ÷ aⁿ = aᵐ ⁻ ⁿ
  3. a⁻ᵐ = 1/aᵐ
  4. a⁻¹ = 1/a
  5. (ab)ᵐ = aᵐ × bᵐ
  6. (a/b)ᵐ = aᵐ / bᵐ
  7. a⁰ = 1

Thanks !

Similar questions