Question

solve by using quadratic formula 1/a+1-1/a+3=1/2​

Answer 1

Answer:

$\frac{1}{a+1}-\frac{1}{a+3}=\frac{1}2\\\\LCM\\\frac{a+3-(a+1)}{(a+1)(a+3)}=\frac{1}2\\\\\frac{a+3-a-1}{(a+1)(a+3)}=\frac{1}2\\\\\frac{2}{(a+1)(a+3)}=\frac{1}2\\\\4 = (a+1)(a+3)$

a+1 = 4                a+3= 4

a=3                        a=1