Question

solve by using quadratic formula :x^2-3x+1=0​

Answer 1

Answer:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

−

3

+

1

=

0

x^{2}-3x+1=0

x2−3x+1=0

=

1

a={\color{#c92786}{1}}

a=1

=

−

3

b={\color{#e8710a}{-3}}

b=−3

=

1

c={\color{#129eaf}{1}}

c=1

=

−

(

−

3

)

±

(

−

3

)

2

−

4

⋅

1

⋅

1

√

2

⋅

1

2

Answer 2

Step-by-step explanation:

-b± [b^2-4ac ]^1/2 /2a

3±[9-4]^1/2 /2

3± 5^ 1/2/2.

x=3+5^1/2 / 2 or x= 3-5^1/2 /2