solve by using quadratic formula x^2-3x+1=0
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Answer:
x = (-b-√D/2a), (-b+√D/2a)
D = b^2-4ac
= (-3)^2 - 4*1*1
= 9 -4 = 5
D = 5
x = [ -(-3)-√5/2*1], [-(-3)+√5/2*1]
x = (3-√5/2), (3+√5)
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