Solve by using quadratic formula x²- 3x + 1 = 0
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Given x^2-3x+1=0
here a=1 b= -3 and c=1
By quadratic formula we have ,
x= -b+- root b^2-4ac ÷ 2a
x= 3+- root 9-4÷2
x= 3+ root 5÷2 or 3-root 5 ÷2
I Hope it helps ☺️
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