solve by using substitution method 2x-y=5and3x+2y=11
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2x-y=5 ................(1)
3X+2Y=11.............(2)
Then,
X=5+Y/2 .......(3)
putting the value of X in equation 2
3X+2Y=11
3×5+Y/2+2Y=11
Then y=1
putting the value of Y in equation 3
X=5+Y/2
Then X=3
Hence X=3 ,Y=1
3X+2Y=11.............(2)
Then,
X=5+Y/2 .......(3)
putting the value of X in equation 2
3X+2Y=11
3×5+Y/2+2Y=11
Then y=1
putting the value of Y in equation 3
X=5+Y/2
Then X=3
Hence X=3 ,Y=1
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