Math, asked by muktichari22, 1 month ago

solve by using substitution method​

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Answers

Answered by bangtanssonyondan
3

Answer:

3x-5y-4=0 (equation 1)

9x=2y+7

9x-2y-7=0 (equation 2)

Solving equation 1

3x-5y-4=0

3x=5y+4

X=5y+4/3

Putting value of x in equation 2

9x-2y-7=0

9(5y+4/3)-2y-7=0

45y+36/3-2y/1-7/1=0

45y+36-6y-21/3=0

39y+15/3=0

39y+15=0*3

39y+15=0

39y=-15

Y=-15/39

Y=-5/13

Putting value of y in equation 1

3x-5y-4=0

3x-5(-5/13)-4=0

3x-25/13-4=0

3x-25-4/13=0

39x-25-52/13=0

39x-25-52=0

39x-77=0

39x=77

X=77/39

Therefore x=77/39

Y=5/13

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