solve by using substitution method
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3x-5y-4=0 (equation 1)
9x=2y+7
9x-2y-7=0 (equation 2)
Solving equation 1
3x-5y-4=0
3x=5y+4
X=5y+4/3
Putting value of x in equation 2
9x-2y-7=0
9(5y+4/3)-2y-7=0
45y+36/3-2y/1-7/1=0
45y+36-6y-21/3=0
39y+15/3=0
39y+15=0*3
39y+15=0
39y=-15
Y=-15/39
Y=-5/13
Putting value of y in equation 1
3x-5y-4=0
3x-5(-5/13)-4=0
3x-25/13-4=0
3x-25-4/13=0
39x-25-52/13=0
39x-25-52=0
39x-77=0
39x=77
X=77/39
Therefore x=77/39
Y=5/13
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